Integrand size = 9, antiderivative size = 15 \[ \int \left (-x^3+x^4\right ) \, dx=-\frac {x^4}{4}+\frac {x^5}{5} \]
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Time = 0.00 (sec) , antiderivative size = 15, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \left (-x^3+x^4\right ) \, dx=\frac {x^5}{5}-\frac {x^4}{4} \]
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Rubi steps \begin{align*} \text {integral}& = -\frac {x^4}{4}+\frac {x^5}{5} \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 15, normalized size of antiderivative = 1.00 \[ \int \left (-x^3+x^4\right ) \, dx=-\frac {x^4}{4}+\frac {x^5}{5} \]
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Time = 0.01 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.73
method | result | size |
gosper | \(\frac {x^{4} \left (-5+4 x \right )}{20}\) | \(11\) |
default | \(-\frac {1}{4} x^{4}+\frac {1}{5} x^{5}\) | \(12\) |
norman | \(-\frac {1}{4} x^{4}+\frac {1}{5} x^{5}\) | \(12\) |
risch | \(-\frac {1}{4} x^{4}+\frac {1}{5} x^{5}\) | \(12\) |
parallelrisch | \(-\frac {1}{4} x^{4}+\frac {1}{5} x^{5}\) | \(12\) |
parts | \(-\frac {1}{4} x^{4}+\frac {1}{5} x^{5}\) | \(12\) |
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none
Time = 0.21 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.73 \[ \int \left (-x^3+x^4\right ) \, dx=\frac {1}{5} \, x^{5} - \frac {1}{4} \, x^{4} \]
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Time = 0.01 (sec) , antiderivative size = 8, normalized size of antiderivative = 0.53 \[ \int \left (-x^3+x^4\right ) \, dx=\frac {x^{5}}{5} - \frac {x^{4}}{4} \]
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none
Time = 0.20 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.73 \[ \int \left (-x^3+x^4\right ) \, dx=\frac {1}{5} \, x^{5} - \frac {1}{4} \, x^{4} \]
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none
Time = 0.28 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.73 \[ \int \left (-x^3+x^4\right ) \, dx=\frac {1}{5} \, x^{5} - \frac {1}{4} \, x^{4} \]
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Time = 0.05 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.67 \[ \int \left (-x^3+x^4\right ) \, dx=\frac {x^4\,\left (4\,x-5\right )}{20} \]
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